Question

10 multiple choice 0.5 points what is the average velocity from d (30 s, 0 m) to f (50 s, -53 m)? table 2.1 position of the car at various times position t (s) x (m) a 0 30 b 10 52 c 20 38 d 30 0 e 40 -37 f 50 -53 -1.06 m/s +1.06 m/s +2.65 m/s -2.65 m/s

Explanation:

Step1: Recall average velocity formula

Average velocity is $\bar{v} = \frac{\Delta x}{\Delta t} = \frac{x_f - x_i}{t_f - t_i}$

Step2: Identify given values

$x_i = 0\ \text{m}$, $t_i = 30\ \text{s}$, $x_f = -53\ \text{m}$, $t_f = 50\ \text{s}$

Step3: Calculate displacement

$\Delta x = x_f - x_i = -53 - 0 = -53\ \text{m}$

Step4: Calculate time interval

$\Delta t = t_f - t_i = 50 - 30 = 20\ \text{s}$

Step5: Compute average velocity

$\bar{v} = \frac{-53}{20} = -2.65\ \text{m/s}$

Answer:

-2.65 m/s