Question

1. a 100 - ft steel tape known to be only 99.98 ft long (under standard conditions) was used to record a measurement of 276.22 ft. what is the distance corrected for the erroneous tape? show all calculations for each problem. homework #3

Explanation:

Step1: Identify the error in tape length

The actual length of the tape is 99.98 ft while it is assumed to be 100 ft. The error factor is $\frac{99.98}{100}$.

Step2: Calculate the corrected distance

The measured distance is 276.22 ft. The corrected distance $d$ is given by $d = 276.22\times\frac{99.98}{100}$.
$d=276.22\times0.9998 = 276.164756$ ft.

Answer:

276.164756 ft