Question

1. choose the the answer.

a container of gas has an unknown initial volume with a temperature of 10.0 °c. the final volume is found to be 3.5 l at a temperature of 50.0 °c. what was the initial volume?
○ 0.70 l
○ 3.9 l
○ 3.1 l

Explanation:

Step1: Convert temps to Kelvin

$T_1 = 10.0 + 273.15 = 283.15\ \text{K}$
$T_2 = 50.0 + 273.15 = 323.15\ \text{K}$

Step2: Apply Charles's Law

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$
Rearrange to solve for $V_1$: $V_1 = V_2 \times \frac{T_1}{T_2}$

Step3: Substitute values

$V_1 = 3.5\ \text{L} \times \frac{283.15}{323.15}$
$V_1 = 3.5\ \text{L} \times 0.876 \approx 3.1\ \text{L}$

Answer:

3.1 L