Question

1. rotate △fev 90° counterclockwise about the point (0,1) to create △fev. then list the coordinates of each figure.

Explanation:

Step1: Recall rotation formula

For a 90 - degree counter - clockwise rotation about a point $(a,b)$, the transformation for a point $(x,y)$ is given by $(x',y')=(a-(y - b),b+(x - a))$.

Step2: Assume coordinates of $\triangle FEV$

Let's assume the coordinates of points $F(x_1,y_1)$, $E(x_2,y_2)$, and $V(x_3,y_3)$. Here the center of rotation is $(a = 0,b = 1)$.
For point $F$:
$x_1'=0-(y_1 - 1)=1 - y_1$
$y_1'=1+(x_1 - 0)=1 + x_1$
For point $E$:
$x_2'=0-(y_2 - 1)=1 - y_2$
$y_2'=1+(x_2 - 0)=1 + x_2$
For point $V$:
$x_3'=0-(y_3 - 1)=1 - y_3$
$y_3'=1+(x_3 - 0)=1 + x_3$

Step3: Read coordinates from the graph (assume)

Suppose $F(-3,3)$, $E(-1,4)$, $V(1,2)$
For $F(-3,3)$:
$x_F'=1 - 3=-2$
$y_F'=1+( - 3)=-2$
For $E(-1,4)$:
$x_E'=1 - 4=-3$
$y_E'=1+( - 1)=0$
For $V(1,2)$:
$x_V'=1 - 2=-1$
$y_V'=1+1 = 2$

Answer:

Pre - I	Image
$E(-1,4)$	$E'(-3,0)$
$V(1,2)$	$V'(-1,2)$