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Question
- write the equation for average velocity and define all the variables. 12. sloth feed and live on cecropia trees which grow to an average height of 49 feet. if a sloth climbs from the bottom of the tree to the top with an average velocity of 0.22 $\frac{ft}{s}$, how much time does it take to reach the bottom?
Question 11
Step1: Recall average velocity formula
The formula for average velocity ($v_{avg}$) is the displacement ($\Delta x$) divided by the time interval ($\Delta t$) over which the displacement occurs. So the equation is $v_{avg} = \frac{\Delta x}{\Delta t}$.
Step2: Define variables
- $v_{avg}$: Represents the average velocity of an object. It is a vector quantity (in the context of displacement) but can be treated as a scalar for one - dimensional motion with constant direction, and its units depend on the units of displacement and time (e.g., meters per second, feet per second).
- $\Delta x$: Represents the displacement of the object. Displacement is the change in position of the object, i.e., the final position minus the initial position ($\Delta x=x_f - x_i$), and its units are units of length (e.g., meters, feet).
- $\Delta t$: Represents the time interval during which the displacement occurs. It is the final time minus the initial time ($\Delta t=t_f - t_i$), and its units are units of time (e.g., seconds, minutes).
Step1: Identify the formula to use
We know the formula for average velocity $v_{avg}=\frac{\Delta x}{\Delta t}$. We need to solve for time $t$ (here $\Delta t$ is the time we want to find, and since the sloth moves from the bottom to the top, the displacement $\Delta x$ is equal to the height of the tree, which is 49 feet, and the average velocity $v_{avg} = 0.22\frac{ft}{s}$). Rearranging the formula for $\Delta t$, we get $\Delta t=\frac{\Delta x}{v_{avg}}$.
Step2: Substitute the values
We have $\Delta x = 49\ ft$ and $v_{avg}=0.22\ \frac{ft}{s}$. Substituting these values into the formula $\Delta t=\frac{\Delta x}{v_{avg}}$, we get $\Delta t=\frac{49}{0.22}$.
Step3: Calculate the value
$\frac{49}{0.22}\approx222.73\ s$ (we perform the division: $49\div0.22\approx222.73$).
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The equation for average velocity is $v_{avg}=\frac{\Delta x}{\Delta t}$, where $v_{avg}$ is the average velocity, $\Delta x$ is the displacement, and $\Delta t$ is the time interval.