Question

11x - 6 = -5x - 4
+ 5x + 5x
16x - 6 = -4

• -

=

Explanation:

Step1: Eliminate constant on left

To isolate the term with $x$, we need to cancel out $-6$ on the left side. We do this by adding 6 to both sides (equivalent to subtracting $-6$, which matches the subtraction blank format: subtract $-6$ is same as add 6, but following the blank structure, we fill in $(-6)$ or directly use the inverse operation step).
Wait, correction: To balance the equation, we add 6 to both sides, which is the same as subtracting $-6$. But the blanks are for subtraction, so we subtract $-6$ (fill blanks with $6$? No, wait: current equation is $16x - 6 = -4$. To move the $-6$ to the right, we add 6 to both sides, which is equivalent to subtracting $-6$ from both sides. So the blanks are filled with $6$ (since $-(6)$ would be wrong, no: step is to add 6 to both sides, so in the subtraction format, it's subtracting $-6$, but the blank is the number to subtract. Wait, no:

Step1: Add 6 to both sides

We add 6 to each side to cancel $-6$ on left.
$16x - 6 + 6 = -4 + 6$

Step2: Simplify both sides

Calculate the constants on each side.
$16x = 2$

Step3: Solve for x

Divide both sides by 16.
$x = \frac{2}{16} = \frac{1}{8}$

But filling the blanks in the given structure:
First, the subtraction blanks (to eliminate $-6$ on left, we add 6, which is subtracting $-6$, so the blanks are both $6$ (since $16x -6 - (-6) = -4 - (-6)$ which is same as adding 6). Then the next line is $16x = 2$.

Answer:

Blanks (top row, left to right): $6$, $6$
Blanks (bottom row, left to right): $16x$, $2$
Final solution for $x$: $\boldsymbol{\frac{1}{8}}$