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12. an elevator began at an elevation of 85.5 feet and ascended at a ra…

Question

  1. an elevator began at an elevation of 85.5 feet and ascended at a rate of 2.75 feet per second. what was the elevation of the elevator after 8 seconds?

Explanation:

Step1: Calculate the distance ascended in 8 seconds

The elevator ascends at a rate of 2.75 feet per second. To find the distance ascended in 8 seconds, we use the formula \( \text{distance} = \text{rate} \times \text{time} \). So, the distance ascended is \( 2.75 \times 8 \).
\( 2.75 \times 8 = 22 \)

Step2: Add the initial elevation to the distance ascended

The initial elevation is 85.5 feet. We add the distance ascended (22 feet) to the initial elevation to find the final elevation. So, the final elevation is \( 85.5 + 22 \).
\( 85.5 + 22 = 107.5 \)

Answer:

The elevation of the elevator after 8 seconds is 107.5 feet.