Question

1. an object is pulled with three forces: one at 20 n to the right, another at 40 n to the right, and the third at 30 n to the left. the net force is a) 60 n to the right. b) 60 n to the left. c) 30 n to the left.

Explanation:

Step1: Calculate right - ward forces sum

Let the right - ward forces be positive. The sum of right - ward forces $F_{right}=20 + 40=60$ N.

Step2: Calculate net force

The left - ward force $F_{left}=30$ N. The net force $F_{net}=F_{right}-F_{left}=60 - 30 = 30$ N. Since $F_{net}>0$, the direction is to the right.

Answer:

A. 60 N to the right.