Question

1. use the following function for the given problems.

$f(x) = -2x + 7$ $g(x) = 2(x+15)$
$f(3) = \underline{\quad 1 \quad}$ $h(-2) = \underline{\quad 5 \quad}$
$g(x) = -7$; when $x = \underline{\quad \quad}$

Explanation:

Step1: Verify f(3) calculation

Substitute $x=3$ into $f(x)$:
$f(3) = -2(3) + 7 = -6 + 7$

Step2: Solve for g(x)=-7

Set $2(x+15) = -7$, isolate $x$:
First divide both sides by 2: $x+15 = \frac{-7}{2}$
Then subtract 15: $x = \frac{-7}{2} - 15 = \frac{-7}{2} - \frac{30}{2}$

Answer:

$f(3) = 1$ (already correct)
$h(-2)$: No function $h(x)$ is provided, cannot solve.
$g(x) = -7$ when $x = -\frac{37}{2}$ (or $-18.5$)