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12. what is $(5x - 1)(8x^{2} - 3x - 6)$? a. $39x^{3} - 23x^{2} - 27x - …

Question

  1. what is $(5x - 1)(8x^{2} - 3x - 6)$?

a. $39x^{3} - 23x^{2} - 27x - 6$
b. $40x^{3} - 38x^{2} + 7x$
c. $40x^{3} - 37x^{2} + 6x$
d. $40x^{3} - 23x^{2} - 27x + 6$

Explanation:

Step1: Distribute $5x$ to each term

$5x(8x^2 - 3x - 6) = 40x^3 - 15x^2 - 30x$

Step2: Distribute $-1$ to each term

$-1(8x^2 - 3x - 6) = -8x^2 + 3x + 6$

Step3: Combine like terms

$40x^3 - 15x^2 - 30x -8x^2 +3x +6 = 40x^3 -23x^2 -27x +6$

Answer:

d. $40x^3 - 23x^2 - 27x + 6$