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13) $sqrt{15}(sqrt{3} + 2)$ 14) $sqrt{6}(sqrt{2} + sqrt{3})$ 15) $sqrt{…

Question

  1. $sqrt{15}(sqrt{3} + 2)$
  2. $sqrt{6}(sqrt{2} + sqrt{3})$
  3. $sqrt{10}(sqrt{10} + 2)$
  4. $sqrt{5}(sqrt{5} + 3)$
  5. $sqrt{5}(5 + sqrt{5})$
  6. $sqrt{15}(sqrt{3} + sqrt{10})$
  7. $-5sqrt{3}(2 + sqrt{5})$
  8. $sqrt{3}(5 + sqrt{2})$
  9. $sqrt{10}(4sqrt{2} + sqrt{5})$
  10. $3sqrt{6}(sqrt{10} - sqrt{3})$
  11. $-4sqrt{5}(4 - 3sqrt{10})$
  12. $sqrt{5}(-4sqrt{6} + sqrt{10})$

Explanation:

Response

Let's solve each problem one by one using the distributive property (also known as the distributive law of multiplication over addition/subtraction), which states that \(a(b + c)=ab+ac\).

Problem 13: \(\boldsymbol{\sqrt{15}(\sqrt{3}+2)}\)

Step1: Apply the distributive property

\(\sqrt{15}\times\sqrt{3}+\sqrt{15}\times2\)
We know that \(\sqrt{a}\times\sqrt{b}=\sqrt{ab}\), so \(\sqrt{15}\times\sqrt{3}=\sqrt{15\times3}=\sqrt{45}=\sqrt{9\times5} = 3\sqrt{5}\) and \(\sqrt{15}\times2 = 2\sqrt{15}\)

Step2: Combine the terms

\(3\sqrt{5}+2\sqrt{15}\)

Answer:

\(3\sqrt{5}+2\sqrt{15}\)

Problem 14: \(\boldsymbol{\sqrt{6}(\sqrt{2}+\sqrt{3})}\)

Step1: Apply the distributive property

\(\sqrt{6}\times\sqrt{2}+\sqrt{6}\times\sqrt{3}\)
Using \(\sqrt{a}\times\sqrt{b}=\sqrt{ab}\), we have \(\sqrt{6}\times\sqrt{2}=\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\) and \(\sqrt{6}\times\sqrt{3}=\sqrt{18}=\sqrt{9\times2} = 3\sqrt{2}\)

Step2: Combine the terms

\(2\sqrt{3}+3\sqrt{2}\)