QUESTION IMAGE
Question
- \\(\frac{sqrt{25}}{sqrt{15}}\\)\
- \\(\frac{sqrt{5}}{sqrt{15}}\\)\
- \\(\frac{sqrt{10}}{sqrt{6}}\\)\
- \\(\frac{sqrt{15}}{sqrt{6}}\\)\
- \\(\frac{sqrt{8}}{sqrt{6}}\\)\
- \\(\frac{sqrt{6}}{sqrt{15}}\\)\
- \\(\frac{3sqrt{3}}{sqrt{5}}\\)\
- \\(\frac{3sqrt{3}}{5sqrt{2}}\\)\
- \\(\frac{4}{3sqrt{5}}\\)\
- \\(\frac{2sqrt{2}}{2sqrt{3}}\\)\
- \\(\frac{5sqrt{4}}{sqrt{5}}\\)\
- \\(\frac{3sqrt{5}}{2sqrt{2}}\\)
Let's solve each problem step by step using the rule of rationalizing the denominator (or simplifying the square root fraction) which is $\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}$ and for rationalizing, we multiply numerator and denominator by the denominator's square root to eliminate the square root from the denominator.
Problem 13: $\frac{\sqrt{25}}{\sqrt{15}}$
Step 1: Simplify $\sqrt{25}$
$\sqrt{25} = 5$, so the expression becomes $\frac{5}{\sqrt{15}}$
Step 2: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{15}$: $\frac{5\times\sqrt{15}}{\sqrt{15}\times\sqrt{15}}=\frac{5\sqrt{15}}{15}$
Step 3: Simplify the fraction
Divide numerator and denominator by 5: $\frac{\sqrt{15}}{3}$
Problem 14: $\frac{\sqrt{5}}{\sqrt{15}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{5}}{\sqrt{15}}=\sqrt{\frac{5}{15}}=\sqrt{\frac{1}{3}}$
Step 2: Rationalize the square root
$\sqrt{\frac{1}{3}}=\frac{\sqrt{1}}{\sqrt{3}}=\frac{1}{\sqrt{3}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{3}$: $\frac{1\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}=\frac{\sqrt{3}}{3}$
Problem 15: $\frac{\sqrt{10}}{\sqrt{6}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{10}}{\sqrt{6}}=\sqrt{\frac{10}{6}}=\sqrt{\frac{5}{3}}$
Step 2: Rationalize the square root
$\sqrt{\frac{5}{3}}=\frac{\sqrt{5}}{\sqrt{3}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{3}$: $\frac{\sqrt{5}\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}=\frac{\sqrt{15}}{3}$
Problem 16: $\frac{\sqrt{15}}{\sqrt{6}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{15}}{\sqrt{6}}=\sqrt{\frac{15}{6}}=\sqrt{\frac{5}{2}}$
Step 2: Rationalize the square root
$\sqrt{\frac{5}{2}}=\frac{\sqrt{5}}{\sqrt{2}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{2}$: $\frac{\sqrt{5}\times\sqrt{2}}{\sqrt{2}\times\sqrt{2}}=\frac{\sqrt{10}}{2}$
Problem 17: $\frac{\sqrt{8}}{\sqrt{6}}$
Step 1: Simplify $\sqrt{8}$
$\sqrt{8} = 2\sqrt{2}$, so the expression becomes $\frac{2\sqrt{2}}{\sqrt{6}}$
Step 2: Use the square root fraction rule
$\frac{2\sqrt{2}}{\sqrt{6}}=2\sqrt{\frac{2}{6}}=2\sqrt{\frac{1}{3}}$
Step 3: Rationalize the square root
$2\sqrt{\frac{1}{3}}=\frac{2}{\sqrt{3}}$
Step 4: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{3}$: $\frac{2\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}=\frac{2\sqrt{3}}{3}$
Problem 18: $\frac{\sqrt{6}}{\sqrt{15}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{6}}{\sqrt{15}}=\sqrt{\frac{6}{15}}=\sqrt{\frac{2}{5}}$
Step 2: Rationalize the square root
$\sqrt{\frac{2}{5}}=\frac{\sqrt{2}}{\sqrt{5}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{5}$: $\frac{\sqrt{2}\times\sqrt{5}}{\sqrt{5}\times\sqrt{5}}=\frac{\sqrt{10}}{5}$
Problem 19: $\frac{3\sqrt{3}}{\sqrt{5}}$
Step 1: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{5}$: $\frac{3\sqrt{3}\times\sqrt{5}}{\sqrt{5}\times\sqrt{5}}=\frac{3\sqrt{15}}{5}$
Problem 20: $\frac{3\sqrt{3}}{5\sqrt{2}}$
Step 1: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{2}$: $\frac{3\sqrt{3}\times\sqrt{2}}{5\sqrt{2}\times\sqrt{2}}=\frac{3\sqrt{6}}{5\times2}=\frac{3\sqrt{6}}{10}$
Problem 21: $\frac{4}{3\sqrt{5}}$
Step 1: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{5}$: $\frac{4\times\sqrt{5}}{3\sqrt{5}\times\sqrt{5}}=\frac{4\sqrt{5}}{3\times5}=\frac{4\sqrt{5}}{15}$
Problem 22: $\frac{2\sqr…
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Let's solve each problem step by step using the rule of rationalizing the denominator (or simplifying the square root fraction) which is $\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b}}$ and for rationalizing, we multiply numerator and denominator by the denominator's square root to eliminate the square root from the denominator.
Problem 13: $\frac{\sqrt{25}}{\sqrt{15}}$
Step 1: Simplify $\sqrt{25}$
$\sqrt{25} = 5$, so the expression becomes $\frac{5}{\sqrt{15}}$
Step 2: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{15}$: $\frac{5\times\sqrt{15}}{\sqrt{15}\times\sqrt{15}}=\frac{5\sqrt{15}}{15}$
Step 3: Simplify the fraction
Divide numerator and denominator by 5: $\frac{\sqrt{15}}{3}$
Problem 14: $\frac{\sqrt{5}}{\sqrt{15}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{5}}{\sqrt{15}}=\sqrt{\frac{5}{15}}=\sqrt{\frac{1}{3}}$
Step 2: Rationalize the square root
$\sqrt{\frac{1}{3}}=\frac{\sqrt{1}}{\sqrt{3}}=\frac{1}{\sqrt{3}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{3}$: $\frac{1\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}=\frac{\sqrt{3}}{3}$
Problem 15: $\frac{\sqrt{10}}{\sqrt{6}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{10}}{\sqrt{6}}=\sqrt{\frac{10}{6}}=\sqrt{\frac{5}{3}}$
Step 2: Rationalize the square root
$\sqrt{\frac{5}{3}}=\frac{\sqrt{5}}{\sqrt{3}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{3}$: $\frac{\sqrt{5}\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}=\frac{\sqrt{15}}{3}$
Problem 16: $\frac{\sqrt{15}}{\sqrt{6}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{15}}{\sqrt{6}}=\sqrt{\frac{15}{6}}=\sqrt{\frac{5}{2}}$
Step 2: Rationalize the square root
$\sqrt{\frac{5}{2}}=\frac{\sqrt{5}}{\sqrt{2}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{2}$: $\frac{\sqrt{5}\times\sqrt{2}}{\sqrt{2}\times\sqrt{2}}=\frac{\sqrt{10}}{2}$
Problem 17: $\frac{\sqrt{8}}{\sqrt{6}}$
Step 1: Simplify $\sqrt{8}$
$\sqrt{8} = 2\sqrt{2}$, so the expression becomes $\frac{2\sqrt{2}}{\sqrt{6}}$
Step 2: Use the square root fraction rule
$\frac{2\sqrt{2}}{\sqrt{6}}=2\sqrt{\frac{2}{6}}=2\sqrt{\frac{1}{3}}$
Step 3: Rationalize the square root
$2\sqrt{\frac{1}{3}}=\frac{2}{\sqrt{3}}$
Step 4: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{3}$: $\frac{2\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}=\frac{2\sqrt{3}}{3}$
Problem 18: $\frac{\sqrt{6}}{\sqrt{15}}$
Step 1: Use the square root fraction rule
$\frac{\sqrt{6}}{\sqrt{15}}=\sqrt{\frac{6}{15}}=\sqrt{\frac{2}{5}}$
Step 2: Rationalize the square root
$\sqrt{\frac{2}{5}}=\frac{\sqrt{2}}{\sqrt{5}}$
Step 3: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{5}$: $\frac{\sqrt{2}\times\sqrt{5}}{\sqrt{5}\times\sqrt{5}}=\frac{\sqrt{10}}{5}$
Problem 19: $\frac{3\sqrt{3}}{\sqrt{5}}$
Step 1: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{5}$: $\frac{3\sqrt{3}\times\sqrt{5}}{\sqrt{5}\times\sqrt{5}}=\frac{3\sqrt{15}}{5}$
Problem 20: $\frac{3\sqrt{3}}{5\sqrt{2}}$
Step 1: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{2}$: $\frac{3\sqrt{3}\times\sqrt{2}}{5\sqrt{2}\times\sqrt{2}}=\frac{3\sqrt{6}}{5\times2}=\frac{3\sqrt{6}}{10}$
Problem 21: $\frac{4}{3\sqrt{5}}$
Step 1: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{5}$: $\frac{4\times\sqrt{5}}{3\sqrt{5}\times\sqrt{5}}=\frac{4\sqrt{5}}{3\times5}=\frac{4\sqrt{5}}{15}$
Problem 22: $\frac{2\sqrt{2}}{2\sqrt{3}}$
Step 1: Simplify the fraction by dividing numerator and denominator by 2
$\frac{\sqrt{2}}{\sqrt{3}}$
Step 2: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{3}$: $\frac{\sqrt{2}\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}=\frac{\sqrt{6}}{3}$
Problem 23: $\frac{5\sqrt{4}}{\sqrt{5}}$
Step 1: Simplify $\sqrt{4}$
$\sqrt{4} = 2$, so the expression becomes $\frac{5\times2}{\sqrt{5}}=\frac{10}{\sqrt{5}}$
Step 2: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{5}$: $\frac{10\times\sqrt{5}}{\sqrt{5}\times\sqrt{5}}=\frac{10\sqrt{5}}{5}=2\sqrt{5}$
Problem 24: $\frac{3\sqrt{5}}{2\sqrt{2}}$
Step 1: Rationalize the denominator
Multiply numerator and denominator by $\sqrt{2}$: $\frac{3\sqrt{5}\times\sqrt{2}}{2\sqrt{2}\times\sqrt{2}}=\frac{3\sqrt{10}}{2\times2}=\frac{3\sqrt{10}}{4}$
Final Answers:
- $\boldsymbol{\frac{\sqrt{15}}{3}}$
- $\boldsymbol{\frac{\sqrt{3}}{3}}$
- $\boldsymbol{\frac{\sqrt{15}}{3}}$
- $\boldsymbol{\frac{\sqrt{10}}{2}}$
- $\boldsymbol{\frac{2\sqrt{3}}{3}}$
- $\boldsymbol{\frac{\sqrt{10}}{5}}$
- $\boldsymbol{\frac{3\sqrt{15}}{5}}$
- $\boldsymbol{\frac{3\sqrt{6}}{10}}$
- $\boldsymbol{\frac{4\sqrt{5}}{15}}$
- $\boldsymbol{\frac{\sqrt{6}}{3}}$
- $\boldsymbol{2\sqrt{5}}$
- $\boldsymbol{\frac{3\sqrt{10}}{4}}$