QUESTION IMAGE
Question
13.) how much distance did the object travel during the entire trip? 14.) how long did the trip take? 15.) what is the average speed for the entire trip? distance vs. time
Step1: Determine the start - time and end - time
The start - time is 0 seconds and the end - time is 6 seconds. So the time taken for the trip is \(t = 6 - 0=6\) seconds.
Step2: Determine the start - distance and end - distance
The start - distance is 0 meters and the end - distance is 0 meters. To find the total distance traveled, we need to consider the absolute values of the changes in distance. From \(t = 0\) to \(t = 1\), the distance changes from 0 to 5. From \(t = 1\) to \(t = 2\), it stays at 5. From \(t = 2\) to \(t = 3\), it changes from 5 to 0. From \(t = 3\) to \(t = 6\), it goes from 0 to 5 and back to 0. The total distance \(d=5 + 0+5+5 = 15\) meters.
Step3: Calculate the average speed
The formula for average speed is \(v=\frac{d}{t}\). Substituting \(d = 15\) meters and \(t = 6\) seconds, we get \(v=\frac{15}{6}=2.5\) m/s.
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- 15 meters
- 6 seconds
- 2.5 m/s