Question

14 \\(\frac{}{105}=\underline{}\\) =\
16 \\(\frac{42}{140}=\underline{}\\) =\
18 \\(\frac{33}{121}=\underline{}\\) =\
© 2013 mat

Explanation:

Problem 16: Simplify $\boldsymbol{\frac{42}{140}}$

Step1: Find GCD of 42 and 140

The greatest common divisor (GCD) of 42 and 140. Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42. Factors of 140: 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140. GCD is 14.

Step2: Divide numerator and denominator by GCD

$\frac{42\div14}{140\div14} = \frac{3}{10}$

Step1: Find GCD of 33 and 121

Factors of 33: 1, 3, 11, 33. Factors of 121: 1, 11, 121. GCD is 11.

Step2: Divide numerator and denominator by GCD

$\frac{33\div11}{121\div11} = \frac{3}{11}$

Answer:

$\frac{3}{10}$

Problem 18: Simplify $\boldsymbol{\frac{33}{121}}$