Question

1. $-7 = n + 10$
2. $-20 = 5n$
3. $r - 5 = -2$

Explanation:

Problem 14: $-7 = n + 10$

Step1: Subtract 10 from both sides

To isolate \( n \), we subtract 10 from both sides of the equation.
\( -7 - 10 = n + 10 - 10 \)

Step2: Simplify both sides

Simplifying the left side: \( -7 - 10 = -17 \)
Simplifying the right side: \( n + 10 - 10 = n \)
So we get \( n = -17 \)

Step1: Divide both sides by 5

To solve for \( n \), we divide both sides of the equation by 5.
\( \frac{-20}{5}=\frac{5n}{5} \)

Step2: Simplify both sides

Simplifying the left side: \( \frac{-20}{5}=-4 \)
Simplifying the right side: \( \frac{5n}{5}=n \)
So we get \( n = -4 \)

Step1: Add 5 to both sides

To isolate \( r \), we add 5 to both sides of the equation.
\( r - 5 + 5=-2 + 5 \)

Step2: Simplify both sides

Simplifying the left side: \( r-5 + 5=r \)
Simplifying the right side: \( -2 + 5 = 3 \)
So we get \( r = 3 \)

Answer:

\( n = -17 \)

Problem 16: $-20 = 5n$