Question

1. a gas occupies 8.0 l at 2.0 atm. what volume will it occupy at 4.0 atm (temperature constant)?

a. 2.0 l
b. 8.0 l
c. 4.0 l
d. 16.0 l

1. a 2.0 l gas is at 300 k. what is its volume at 600 k if pressure remains constant?

a. 1.0 l
b. 2.0 l
c. 4.0 l
d. 3.0 l

Explanation:

Step1: Identify the gas - law for question 14

Boyle's law: $P_1V_1 = P_2V_2$ (temperature constant).
Given $P_1 = 2.0$ atm, $V_1=8.0$ L, $P_2 = 4.0$ atm.
We need to find $V_2$.
$V_2=\frac{P_1V_1}{P_2}$

Step2: Calculate $V_2$ for question 14

$V_2=\frac{2.0\text{ atm}\times8.0\text{ L}}{4.0\text{ atm}} = 4.0$ L

Step3: Identify the gas - law for question 15

Charles's law: $\frac{V_1}{T_1}=\frac{V_2}{T_2}$ (pressure constant).
Given $V_1 = 2.0$ L, $T_1 = 300$ K, $T_2=600$ K.
We need to find $V_2$.
$V_2=\frac{V_1T_2}{T_1}$

Step4: Calculate $V_2$ for question 15

$V_2=\frac{2.0\text{ L}\times600\text{ K}}{300\text{ K}}=4.0$ L

Answer:

1. C. 4.0 L
2. C. 4.0 L