Question

1. the perimeter of a rectangle is 60 in. the length is 12 in. find the area.

Explanation:

Step1: Recall perimeter formula

The perimeter formula of a rectangle is $P = 2(l + w)$, where $P$ is perimeter, $l$ is length and $w$ is width. Given $P = 60$ in and $l=12$ in. Substitute into the formula: $60 = 2(12 + w)$.

Step2: Solve for width

First, divide both sides of the equation $60 = 2(12 + w)$ by 2: $\frac{60}{2}=12 + w$, so $30=12 + w$. Then subtract 12 from both sides: $w=30 - 12=18$ in.

Step3: Recall area formula

The area formula of a rectangle is $A=l\times w$. Now that $l = 12$ in and $w = 18$ in, substitute these values into the formula.

Step4: Calculate area

$A=12\times18 = 216$ in².

Answer:

216 in²