Question

1. factor (0.01x^2 + 0.14x + 0.49) using the perfect square trinomial method (if applicable).

a. not a perfect square trinomial
b. ((0.1x - 0.7)^2)
c. ((0.1x + 0.7)^2)
d. (0.01(x^2 + 49))

Explanation:

Step1: Identify square terms

First term: $0.01x^2=(0.1x)^2$, last term: $0.49=(0.7)^2$

Step2: Verify middle term

Check $2\times0.1x\times0.7=0.14x$, matches given middle term.

Step3: Write perfect square form

Since all conditions are met, the trinomial factors to $(0.1x + 0.7)^2$.

Answer:

c. $(0.1x + 0.7)^2$