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Question
3 in 16 in 8 in 8 in 4 in 3 in 11 in 141 square inches 62 square inches 53 square inches 129 square inches
Step1: Split shape into 3 parts
Divide the figure into a trapezoid, a rectangle, and a smaller rectangle.
Step2: Calculate trapezoid area
Use trapezoid area formula: $\frac{1}{2} \times (a + b) \times h$ where $a=3$, $b=8$, $h=16-4=12$.
$\frac{1}{2} \times (3 + 8) \times 12 = \frac{1}{2} \times 11 \times 12 = 66$ square inches
Step3: Calculate middle rectangle area
Area = length $\times$ width, length $=11-8=3$, width $=4$.
$3 \times 4 = 12$ square inches
Step4: Calculate right rectangle area
Area = length $\times$ width, length $=8$, width $=3$.
$8 \times 3 = 24$ square inches
Step5: Sum all areas
Add the three calculated areas.
$66 + 12 + 24 = 102$
Wait, correction: Re-split the shape correctly:
Step1: Split into 2 parts
Divide into a tall trapezoid and a bottom rectangle.
Step2: Trapezoid dimensions: bases 3, 8; height 16-4=12
$\frac{1}{2} \times (3+8) \times 12 = 66$
Step3: Bottom rectangle: length 11, width 4
$11 \times 4 = 44$
Step4: Right small rectangle: length 8, width 3
$8 \times 3 = 24$
Wait, correct split: The figure is a large shape, alternative split:
Step1: Split into left trapezoid, middle rectangle, right rectangle
Left trapezoid: top=3, bottom=8, height=16-4=12: $\frac{1}{2}(3+8)*12=66$
Middle rectangle: width=11-8=3, height=4: $3*4=12$
Right rectangle: length=8, height=3: $8*3=24$
Total: $66+12+24=102$
Wait, error in initial split: Correct split is:
Step1: Treat as a large rectangle minus missing parts
Large rectangle: width=11, height=16: $11*16=176$
Missing right rectangle: width=8, height=16-3=13: $8*13=104$
Missing left corner: width=11-8=3, height=16-12=4: No, better correct split:
Step1: Split into upper trapezoid and lower L-shape
Upper trapezoid: bases 3, 8, height 12: $\frac{1}{2}(3+8)*12=66$
Lower L-shape: area = $11*4 + 8*3 - 3*4=44+24-12=56$
Total: $66+56=122$
Wait, correct method:
Step1: Split into left trapezoid, middle vertical rectangle, right rectangle
Left trapezoid: top=3, bottom=8, height=16-4=12: $\frac{1}{2}(3+8)*12=66$
Middle rectangle: width=11-8=3, height=16: $3*16=48$
Subtract overlapping rectangle: width=3, height=4: $3*4=12$
Right rectangle: width=8, height=3: $8*3=24$
Total: $66+48-12+24=126$
Wait, let's use the correct split:
The figure is: top side 3, right side 16, bottom right 8, up 3, left 11, up 4, left 8, up to top.
So the shape can be split into:
- A trapezoid with vertices at top left, top right, right middle (16-3=13 down from top), left middle (12 down from top, 8 left from right middle).
Trapezoid area: $\frac{1}{2}(3+8)*(16-3)= \frac{1}{2}*11*13=71.5$
- A rectangle at the bottom: length 11, width 3: $11*3=33$
- A rectangle on the left middle: width 8-3=5, height 4-3=1: $5*1=5$
No, this is wrong. Let's use the shoelace formula:
Coordinates: (0,16), (3,16), (3,0), (11,0), (11,3), (3,3), (3,4), (8,4), (8,16), (0,16)
Wait, correct coordinates:
Top left: (0,16), top right: (3,16), right bottom: (3,0), bottom right: (11,0), up to (11,3), left to (3,3), up to (3,4), left to (8,4), up to (8,16), left to (0,16)
Shoelace formula:
Sum1 = $(0*16)+(3*0)+(3*0)+(11*3)+(11*3)+(3*4)+(3*4)+(8*16)+(8*16)$
= $0+0+0+33+33+12+12+128+128=346$
Sum2 = $(16*3)+(16*3)+(0*11)+(0*11)+(3*3)+(3*3)+(4*8)+(4*8)+(16*0)$
= $48+48+0+0+9+9+32+32+0=178$
Area = $\frac{1}{2}|346-178|=\frac{1}{2}*168=84$
No, this is incorrect. Let's do it properly:
Correct split:
- The tall part: a trapezoid with bases 3 and 8, height 16-4=12. Area = $\frac{1}{2}(3+8)*12=66$
- The bottom part: a rectangle of 11x4, minus the right part that's not there? No, the bottom part is 11x4, and th…
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129 square inches