Question

16 calculate the energy possessed by a single photon whose frequency is 1.05 x 10^16 hz. * (0.5 points) 4.19 x 10^-13 j 1.58 x 10^49 j 3.15 x 10^24 j 6.29 x 10^-20 j 6.31 x 10^-50 j 6.96 x 10^-18 j

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by the formula $E = hf$, where $h$ is Planck's constant ($h=6.63\times 10^{-34}\ J\cdot s$) and $f$ is the frequency of the photon.

Step2: Substitute values

We are given $f = 1.05\times 10^{16}\ Hz$. Substitute $h = 6.63\times 10^{-34}\ J\cdot s$ and $f=1.05\times 10^{16}\ Hz$ into the formula $E = hf$.
$E=(6.63\times 10^{-34}\ J\cdot s)\times(1.05\times 10^{16}\ Hz)$

Step3: Perform multiplication

Using the rule of exponents $a^m\times a^n=a^{m + n}$, we have $E=(6.63\times1.05)\times10^{-34 + 16}\ J$.
$6.63\times1.05 = 6.9615$, and $-34 + 16=-18$. So $E = 6.9615\times 10^{-18}\ J\approx6.96\times 10^{-18}\ J$.

Answer:

$6.96\times 10^{-18}\ J$ (corresponding to the last option)