Question

17 consider the function, $f(x) = 2x - 1$. use the above function to complete the following table.

x	f(x)
-1
0
1
2

Explanation:

Step1: Substitute \( x = -1 \) into \( f(x) = 2x - 1 \)

\( f(-1) = 2\times(-1) - 1 = -2 - 1 = -3 \)

Step2: Substitute \( x = 0 \) into \( f(x) = 2x - 1 \)

\( f(0) = 2\times0 - 1 = 0 - 1 = -1 \)

Step3: Substitute \( x = 1 \) into \( f(x) = 2x - 1 \)

\( f(1) = 2\times1 - 1 = 2 - 1 = 1 \)

Step4: Substitute \( x = 2 \) into \( f(x) = 2x - 1 \)

\( f(2) = 2\times2 - 1 = 4 - 1 = 3 \)

Answer:

When \( x = -1 \), \( f(x) = -3 \); when \( x = 0 \), \( f(x) = -1 \); when \( x = 1 \), \( f(x) = 1 \); when \( x = 2 \), \( f(x) = 3 \). So the completed table is:

\( x \)	\( f(x) \)
0	-1
1	1
2	3