Question

1b. solve the system of equations.\

$$\begin{cases}10x + 2y = -26\\\\-7x - 2y = 20\\end{cases}$$

\bigcirc infinitely many solutions (same line)\bigcirc (-2, -3)\bigcirc no solution (parallel lines)\bigcirc (-2, 3)\bigcirc (2, -3)\bigcirc (-3, -2)

Explanation:

Step1: Add the two equations

$$10x + 2y + (-7x - 2y) = -26 + 20$$
$$3x = -6$$

Step2: Solve for $x$

$$x = \frac{-6}{3} = -2$$

Step3: Substitute $x=-2$ into first equation

$$10(-2) + 2y = -26$$
$$-20 + 2y = -26$$

Step4: Solve for $y$

$$2y = -26 + 20 = -6$$
$$y = \frac{-6}{2} = -3$$

Answer:

(-2, -3)