Question

1. \

$$\begin{cases} x = -2 \\\\ 3x - 2y = -18 \\end{cases}$$

solution:

Explanation:

Step1: Substitute \( x = -2 \) into the second equation

We have the system of equations: \(

$$\begin{cases} x = -2 \\ 3x - 2y = -18 \end{cases}$$

\). Substitute \( x = -2 \) into \( 3x - 2y = -18 \), we get \( 3(-2) - 2y = -18 \).

Step2: Simplify the left - hand side

Calculate \( 3(-2)=-6 \), so the equation becomes \( -6 - 2y = -18 \).

Step3: Solve for \( y \)

First, add 6 to both sides of the equation: \( -2y=-18 + 6=-12 \). Then divide both sides by - 2: \( y=\frac{-12}{-2} = 6 \).

Answer:

The solution of the system of equations is \( x=-2,y = 6 \), or in ordered - pair form \( (-2,6) \)