Question

(\frac{4x^{0}y^{-2}z^{3}}{4x})

Explanation:

Step1: Simplify $x^0$ rule

Any non-zero number to 0 power is 1: $x^0=1$
Expression becomes: $\frac{4 \cdot 1 \cdot y^{-2} z^3}{4x} = \frac{4y^{-2} z^3}{4x}$

Step2: Cancel constant terms

Divide 4 by 4: $\frac{4}{4}=1$
Expression becomes: $\frac{y^{-2} z^3}{x}$

Step3: Rewrite negative exponent

$y^{-2} = \frac{1}{y^2}$
Expression becomes: $\frac{z^3}{x y^2}$

Answer:

$\frac{z^3}{x y^2}$