Question

① \\(\frac{6(r + 2)}{20} cdot \frac{4r}{6r + 12} =\\)

Explanation:

Step1: Simplify the fraction multiplication

We have the expression $\frac{6(r + s)}{20} \cdot \frac{4r}{6(r + s)}$. First, notice that $6(r + s)$ appears in both the numerator of the first fraction and the denominator of the second fraction, so we can cancel them out.
$\frac{\cancel{6(r + s)}}{20} \cdot \frac{4r}{\cancel{6(r + s)}}=\frac{4r}{20}$

Step2: Reduce the remaining fraction

Now, simplify $\frac{4r}{20}$ by dividing both the numerator and the denominator by their greatest common divisor, which is 4.
$\frac{4r\div4}{20\div4}=\frac{r}{5}$

Answer:

$\frac{r}{5}$