Question

1. determine the centripetal force on a 250 g rock in a slingshot with a tangential velocity of 7.6 m/s. the string for the slingshot is 0.45 meter long. 32,000 n 42 n 4,200 n 32 n

Explanation:

Step1: Convert mass to kg

$m = 250\ \text{g} = 0.25\ \text{kg}$

Step2: Recall centripetal force formula

$F_c = \frac{mv^2}{r}$

Step3: Substitute given values

$F_c = \frac{0.25\ \text{kg} \times (7.6\ \text{m/s})^2}{0.45\ \text{m}}$

Step4: Calculate numerator first

$(7.6)^2 = 57.76$, $0.25 \times 57.76 = 14.44$

Step5: Divide by radius

$F_c = \frac{14.44}{0.45} \approx 32\ \text{N}$

Answer:

32 N