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20. the gravitational force between two oranges of masses $m_1 = 500 g$…

Question

  1. the gravitational force between two oranges of masses $m_1 = 500 g$ and $m_2 = 300 g$ separated by 100 cm is (take $g = 1 n.m^2/kg^2$.) (a) 800 n (b) 15 n (c) 1.0 n (d) 0.15 n (e) none of the above

Explanation:

Step1: Convert mass units to kg

$m_1 = 500g=0.5kg$, $m_2 = 300g = 0.3kg$, $r=100cm = 1m$

Step2: Apply gravitational - force formula

The gravitational - force formula is $F = G\frac{m_1m_2}{r^2}$. Substitute $G = 1N\cdot m^2/kg^2$, $m_1 = 0.5kg$, $m_2 = 0.3kg$, and $r = 1m$ into the formula.
$F=1\times\frac{0.5\times0.3}{1^2}$
$F = 0.15N$

Answer:

D. 0.15 N