Question

1. -12 points details my notes ask your teacher practice another osuiphys1 2.2.wa.010. a cheetah is running at a speed of 19.5 m/s in a direction of 66° north of west. find the components of the cheetahs velocity along the following directions. (a) the velocity component due north m/s (b) the velocity component due west m/s resources reading

Explanation:

Step1: Define given values

Speed $v = 19.5$ m/s, angle $\theta = 66^\circ$ north of west

Step2: Calculate north velocity component

Use $\sin\theta$ for north component:
$v_{\text{north}} = v \sin\theta = 19.5 \times \sin(66^\circ)$
$\sin(66^\circ) \approx 0.9135$, so $v_{\text{north}} \approx 19.5 \times 0.9135 \approx 17.81$ m/s

Step3: Calculate west velocity component

Use $\cos\theta$ for west component:
$v_{\text{west}} = v \cos\theta = 19.5 \times \cos(66^\circ)$
$\cos(66^\circ) \approx 0.4067$, so $v_{\text{west}} \approx 19.5 \times 0.4067 \approx 7.93$ m/s

Answer:

(a) 17.8 m/s (rounded to 3 significant figures)
(b) 7.93 m/s (rounded to 3 significant figures)