Question

1. j(-3, 4), k(4, 4), l(3, -3)

Explanation:

Assuming the problem is to find the area of triangle \(JKL\) with vertices \(J(-3, 4)\), \(K(4, 4)\), and \(L(3, -3)\):

Step 1: Find the length of \(JK\)

Since \(J\) and \(K\) have the same \(y\)-coordinate, the distance is the difference in \(x\)-coordinates.
\(JK = |4 - (-3)| = |7| = 7\)

Step 2: Find the height from \(L\) to \(JK\)

The line \(JK\) is horizontal (since \(y = 4\) for both \(J\) and \(K\)). The height is the vertical distance from \(L(3, -3)\) to \(y = 4\), which is \(|4 - (-3)| = 7\)

Step 3: Calculate the area of the triangle

The formula for the area of a triangle is \(\frac{1}{2} \times \text{base} \times \text{height}\).
\(\text{Area} = \frac{1}{2} \times JK \times \text{height} = \frac{1}{2} \times 7 \times 7 = \frac{49}{2} = 24.5\)

Answer:

The area of triangle \(JKL\) is \(\boldsymbol{24.5}\) (or \(\boldsymbol{\frac{49}{2}}\))