Question

b
308
× 7
2,□56
c
1□
445
× 34
□,□80
+ 13,□5□
□□,130

Explanation:

Step1: Solve part b: Multiply units digit

$8 \times 7 = 56$. Write down 6, carry over 5.

Step2: Multiply tens digit + carryover

$0 \times 7 + 5 = 5$. Write down 5, no new carryover.

Step3: Multiply hundreds digit

$3 \times 7 = 21$. Write down 21.

Step4: Combine results for part b

$308 \times 7 = 2156$. The missing digit is 1.

Step5: Solve part c: Multiply by 4 (units of 34)

$445 \times 4 = 1780$. The missing digits are 1 and 7.

Step6: Multiply by 30 (tens of 34)

$445 \times 30 = 13350$. The missing digits are 3 and 0.

Step7: Add the two products

$1780 + 13350 = 15130$. The missing digits are 1 and 5.

Step8: Identify top carryover digits

In $445 \times 4$, tens place: $4 \times 4 = 16$, plus carryover 2 (from $5 \times 4=20$) gives 18, so carryover 1. The top carryover digits are 2 (from units place) and 1 (from tens place).

Answer:

Part b: The missing digit in the product is 1, so the full equation is $308 \times 7 = 2156$
Part c:

• Top carryover digits: 2 (above 4, units place) and 1 (above 4, tens place)
• First partial product: $1,780$
• Second partial product: $13,350$
• Final sum: $15,130$