Question

c) 345×10^{-4} m = \frac{3.45}{}×10^{-3}

Explanation:

Step1: Convert 345 to scientific - notation

On a scale of 1 to 10, $345 = 3.45\times10^{2}$.

Step2: Combine exponents

$345\times10^{- 4}=(3.45\times10^{2})\times10^{-4}$.
According to the rule of exponents $a^{m}\times a^{n}=a^{m + n}$, we have $(3.45\times10^{2})\times10^{-4}=3.45\times10^{2+( - 4)}=3.45\times10^{-2}$.
We want to write it in the form of $3.45\times10^{-3}$, but this is incorrect. The correct form for $345\times10^{-4}$ in scientific - notation is $3.45\times10^{-2}$.

Answer:

The original equation $345\times10^{-4}\text{ m}=3.45\times10^{-3}$ is incorrect. The correct result is $345\times10^{-4}=3.45\times10^{-2}$.