Question

4(3x - 8) < 6x + 4

Explanation:

Step1: Expand the left - hand side

$4(3x - 8)=12x-32$, so the inequality becomes $12x - 32<6x + 4$.

Step2: Move the terms with $x$ to one side

Subtract $6x$ from both sides: $12x-6x - 32<6x-6x + 4$, which simplifies to $6x-32 < 4$.

Step3: Move the constant terms to one side

Add 32 to both sides: $6x-32 + 32<4 + 32$, resulting in $6x<36$.

Step4: Solve for $x$

Divide both sides by 6: $\frac{6x}{6}<\frac{36}{6}$, so $x < 6$.

Answer:

$x < 6$