Question

(5p²+5p-26)÷(p+3); 5p-10, r 4; 5p-12, r 1; 5p-13, r 8; 5p-10, r 5

Explanation:

Step1: Divide leading terms

$\frac{5p^2}{p} = 5p$

Step2: Multiply divisor by 5p

$5p(p+3) = 5p^2 + 15p$

Step3: Subtract from dividend

$(5p^2+5p-26) - (5p^2+15p) = -10p -26$

Step4: Divide new leading term

$\frac{-10p}{p} = -10$

Step5: Multiply divisor by -10

$-10(p+3) = -10p -30$

Step6: Subtract to find remainder

$(-10p-26) - (-10p-30) = 4$

Answer:

5p-10, R 4