Question

is (-6, -1) a solution to this system of equations?
$y = \frac{1}{3}x + 1$
$y = 2x + 11$

yes
no

Explanation:

Step1: Substitute into first - equation

Substitute \(x=-6\) and \(y = - 1\) into \(y=\frac{1}{3}x + 1\).
\(y=\frac{1}{3}x + 1\) becomes \(-1=\frac{1}{3}\times(-6)+1\).
Calculate the right - hand side: \(\frac{1}{3}\times(-6)+1=-2 + 1=-1\). The left - hand side equals the right - hand side for the first equation.

Step2: Substitute into second - equation

Substitute \(x=-6\) and \(y=-1\) into \(y = 2x+11\).
\(y = 2x+11\) becomes \(-1=2\times(-6)+11\).
Calculate the right - hand side: \(2\times(-6)+11=-12 + 11=-1\). The left - hand side equals the right - hand side for the second equation.

Answer:

yes