Question

65.)
rectangle with length 10.4 yd and width 6 yd
66.)
rectangle with length 9.9 mi and width 12 mi

Explanation:

Assuming the problems are about finding the area of rectangles (since they have right angles, indicating rectangles), here are the solutions:

Problem 65 (Area of Rectangle)

Step1: Recall the formula for the area of a rectangle, which is \( A = \text{length} \times \text{width} \).

Step2: Identify the length and width from the diagram. The length is \( 10.4 \) yd and the width is \( 6 \) yd.

Step3: Multiply the length and width: \( A = 6 \times 10.4 \).

Step4: Calculate the product: \( 6 \times 10.4 = 62.4 \) square yards.

Step1: Recall the formula for the area of a rectangle, \( A = \text{length} \times \text{width} \).

Step2: Identify the length and width from the diagram. The length is \( 12 \) mi and the width is \( 9.9 \) mi.

Step3: Multiply the length and width: \( A = 9.9 \times 12 \).

Step4: Calculate the product: \( 9.9 \times 12 = 118.8 \) square miles.

Answer:

The area of the rectangle is \( 62.4 \) square yards.

Problem 66 (Area of Rectangle)