Question

80 n the fridge experiences an applied force of +80 n. what is the acceleration of the fridge? remember: f = ma 210 kg -2.0 m/s² -0.38 m/s² +2.0 m/s² +0.38 m/s²

Explanation:

Step1: Recall the formula \( F = ma \)

We know that \( F \) is force, \( m \) is mass, and \( a \) is acceleration. We need to solve for \( a \), so we can rearrange the formula to \( a=\frac{F}{m} \).

Step2: Identify the values of \( F \) and \( m \)

The applied force \( F = +80\ N \) and the mass of the fridge \( m = 210\ kg \).

Step3: Substitute the values into the formula

Substitute \( F = 80\ N \) and \( m = 210\ kg \) into \( a=\frac{F}{m} \), we get \( a=\frac{80}{210}\approx0.38\ m/s^{2} \). Since the force is positive, the acceleration is also positive.

Answer:

+0.38 m/s²