Question

s+p=0
8s+6p=70
s=8-p
8(8-p)+6p=70
s=8-3
solution types
remember there are 3 types of solutions possible from a system of equations!
identify from a graph/equation or both when a system has one, infinitely many or no solution
exactly one solution
infinitely many solutions
no solutions
notes for myself
*make sure to create a note card 3x5\

Explanation:

Step1: Substitute $s=8-p$ into second equation

$8(8-p)+6p=70$

Step2: Expand and simplify left side

$64-8p+6p=70$
$64-2p=70$

Step3: Isolate the variable term

$-2p=70-64$
$-2p=6$

Step4: Solve for $p$

$p=\frac{6}{-2}=-3$

Step5: Solve for $s$ using $s=8-p$

$s=8-(-3)=8+3=11$

Answer:

$s=11$, $p=-3$