Question

activity 3 • distributed practice
solve.

1. $\frac{3}{4} + \frac{1}{2}$
2. $\frac{2}{3} - \frac{1}{2}$
3. $\frac{5}{3} - \frac{2}{3}$
4. $\frac{1}{6} + \frac{2}{3}$
5. $\frac{8}{10} - \frac{7}{10}$
6. $\frac{7}{7} + \frac{2}{7}$

Explanation:

Step1: Find common denominator

$\frac{3}{4} + \frac{1}{2} = \frac{3}{4} + \frac{2}{4}$

Step2: Add numerators

$\frac{3+2}{4} = \frac{5}{4}$

Step1: Find common denominator

$\frac{2}{3} - \frac{1}{2} = \frac{4}{6} - \frac{3}{6}$

Step2: Subtract numerators

$\frac{4-3}{6} = \frac{1}{6}$

Step1: Subtract numerators (same denominator)

$\frac{5-2}{3} = \frac{3}{3}$

Step2: Simplify fraction

$\frac{3}{3} = 1$

Step1: Find common denominator

$\frac{1}{6} + \frac{2}{3} = \frac{1}{6} + \frac{4}{6}$

Step2: Add numerators

$\frac{1+4}{6} = \frac{5}{6}$

Step1: Subtract numerators (same denominator)

$\frac{8-7}{10} = \frac{1}{10}$

Step1: Add numerators (same denominator)

$\frac{7+2}{7} = \frac{9}{7}$

Answer:

1. $\frac{5}{4}$
2. $\frac{1}{6}$
3. $1$
4. $\frac{5}{6}$
5. $\frac{1}{10}$
6. $\frac{9}{7}$