Question

8.4 add, subtract, and multiply radical expressions
score: 14.8/22 answered: 15/22
question 16
simplify. assume all variables are nonnegative.
(5\sqrt{6y^{2}})(4\sqrt{7y^{6}})=
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Explanation:

Step1: Multiply the coefficients

$5\times4 = 20$

Step2: Multiply the radicands

$\sqrt{6y^{2}}\times\sqrt{7y^{6}}=\sqrt{6y^{2}\times7y^{6}}=\sqrt{42y^{2 + 6}}=\sqrt{42y^{8}}$

Step3: Simplify the square - root

$\sqrt{42y^{8}}=y^{4}\sqrt{42}$

Step4: Combine the results

$20\times y^{4}\sqrt{42}=20y^{4}\sqrt{42}$

Answer:

$20y^{4}\sqrt{42}$