Question

1. addition & subtraction

amy went to the garden store. she bought 965 sunflower seeds, 237 rose seeds, and 568 pumpkin seeds. how many more sunflower seeds did she buy than pumpkin seeds?

1. multiplication

which expression is equivalent to 94×6?
a. (90×4)+(90×6) c. (90×6)+(4×6)
b. (90 + 4)×(4 + 6) d. (90 + 4)+(4 + 6)

1. multi - step word problem

nicole likes to collect coins. in january, nicole found 84 coins, in february, nicole found 236 coins, and in march, nicole found 18 coins. unfortunately in april nicole lost half of her coins that she collected. how many coins does nicole have now?

1. factors & multiples

which list contains the first five multiples of 7?
a. 7, 14, 21, 29, 35 c. 7, 14, 21, 28, 35
b. 7, 21, 28, 35, 42 d. 1, 7

1. adding & subtracting fractions

choose all of the equations that are equivalent to the fraction represented by the area model below.
pie chart image
a. 1/4 + 1/4 + 1/4 + 1/4 c. 1/5 + 1/5 + 1/5 + 1/5
b. 3/5 + 1/5 d. 2/5 + 1/5 + 2/5

1. multiply a fraction by a whole number

kaci, cole and beth each have 4/6 pounds of sunflower seeds. how many sunflower seeds do they have in total?

1. measurement conversions

which statement is true?
a. 7 pounds is greater than 200 ounces
b. 9 quarts is equal to 20 pints
c. 12 yards is less than 40 feet
d. 6 pints is greater than 15 cups

1. measurement conversion word problems

beth went to the store and bought an umbrella for $9.50, a wallet for $6.43, and a candy bar for $1.74. if she paid with a twenty - dollar bill, how much change will she receive?

1. measuring angles

which angle classification best matches the angle below?
protractor - angle image

1. decomposed angles

which two angles when combined together will result in the formation of a right angle?
a. 54° & 39° c. 51° & 49°
b. 63° & 27° d. 18° & 74°

Explanation:

Problem 4

Step1: Subtract pumpkin from sunflower

$965 - 568 = 397$

Problem 5

Step1: Apply distributive property

$94 \times 6 = (90+4) \times 6 = (90 \times 6)+(4 \times 6)$

Problem 9

Step1: Sum total collected coins

$84 + 236 + 18 = 338$

Step2: Calculate remaining coins

$\frac{338}{2} = 169$

Problem 10

Step1: List first 5 multiples of 7

$7 \times 1=7,\ 7 \times 2=14,\ 7 \times 3=21,\ 7 \times 4=28,\ 7 \times 5=35$

Problem 14

Step1: Identify shaded fraction

Shaded area = $\frac{4}{5}$

Step2: Check equivalent equations

Option C: $\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{4}{5}$
Option D: $\frac{2}{5}+\frac{1}{5}+\frac{2}{5}=\frac{5}{5}$ (incorrect, correction: $\frac{2}{5}+\frac{1}{5}+\frac{1}{5}=\frac{4}{5}$ but given D is $\frac{2}{5}+\frac{1}{5}+\frac{2}{5}$, so only C matches. Wait, recheck: the circle has 5 parts, 4 shaded. So sum of 4 $\frac{1}{5}$s, which is option C.

Problem 15

Step1: Multiply by number of people

$3 \times \frac{4}{6} = \frac{12}{6} = 2$

Problem 19

Step1: Convert and compare each option

A. $7 \text{ lbs} = 7 \times 16 = 112 \text{ oz} < 200 \text{ oz}$ (false)
B. $9 \text{ qts} = 9 \times 2 = 18 \text{ pints}
eq 20 \text{ pints}$ (false)
C. $12 \text{ yards} = 12 \times 3 = 36 \text{ ft} < 40 \text{ ft}$ (true)
D. $6 \text{ pints} = 6 \times 2 = 12 \text{ cups} < 15 \text{ cups}$ (false)

Problem 20

Step1: Sum total cost

$9.50 + 6.43 + 1.74 = 17.67$

Step2: Calculate change

$20.00 - 17.67 = 2.33$

Problem 24

Step1: Read protractor measurement

Angle measures $130^\circ$, which is obtuse (between $90^\circ$ and $180^\circ$)

Problem 25

Step1: Find pair summing to $90^\circ$

Option B: $63^\circ + 27^\circ = 90^\circ$

Answer:

1. 397
2. C. $(90×6)+(4×6)$
3. 169
4. C. 7, 14, 21, 28, 35
5. C. $1/5 + 1/5 + 1/5 + 1/5$
6. 2 pounds
7. C. 12 yards is less than 40 feet
8. $\$2.33$
9. Obtuse angle (measure = $130^\circ$)
10. B. $63^\circ$ & $27^\circ$