Question

algebra review

1. evaluate the expression \\(\frac{3a + 2b}{2}\\) when \\(a = -3\\) and \\(b = -4\\).

a) \\(-\frac{1}{2}\\)
b) \\(-\frac{17}{2}\\)
c) \\(\frac{1}{2}\\)
d) \\(\frac{17}{2}\\)

Explanation:

Step1: Substitute $a=-3, b=-4$

$\frac{3(-3) + 2(-4)}{2}$

Step2: Calculate numerator terms

$\frac{-9 + (-8)}{2} = \frac{-17}{2}$

Step3: Simplify the fraction

$\frac{-17}{2}$

Answer:

B) $-\frac{17}{2}$