Question

$y \leq \frac{1}{3}x - 1$
$y \leq \frac{1}{3}x - 3$
\bigcirc all values that satisfy $y \leq \frac{1}{3}x - 1$ are solutions.
\bigcirc all values that satisfy $y \leq \frac{1}{3}x - 3$ are solutions.
\bigcirc all values that satisfy either $y \leq \frac{1}{3}x - 1$ or $y \leq \frac{1}{3}x - 3$ are solutions.
\bigcirc there are no solutions

Explanation:

The system of inequalities is a conjunction (both must be true). The solution set is the overlap of the two shaded regions. The region for $y \leq \frac{1}{3}x - 3$ is entirely contained within the region for $y \leq \frac{1}{3}x - 1$, so all points satisfying the stricter lower inequality satisfy both.

Answer:

All values that satisfy $y \leq \frac{1}{3}x - 3$ are solutions.