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kyra has \\(\frac{33}{8}\\) yards of red ribbon and \\(\frac{23}{3}\\) yards of blue ribbon. about how many yards of ribbon does she have?
round both numbers to the nearest whole number. then add or subtract.
estimate \\(\frac{33}{8} + \frac{23}{3}\\).
\\(\frac{33}{8}\\) is \\(\frac{1}{8}\\) more than \\(\frac{32}{8}\\), which is 4. so \\(\frac{33}{8}\\) rounds to 4.
\\(\frac{23}{3}\\) is \\(\frac{1}{3}\\) less than \\(\frac{24}{3}\\), which is 8. so \\(\frac{23}{3}\\) rounds to 8.
\\(4 + 8 = 12\\)
so, \\(\frac{33}{8} + \frac{23}{3}\\) is about 12.
kyra has about 12 yards of ribbon.
in 1–8, round to the nearest whole number.
- \\(\frac{53}{6}\\)
- \\(13\frac{8}{9}\\)
- \\(\frac{130}{3}\\)
- \\(6\frac{6}{7}\\)
- \\(7\frac{40}{81}\\)
- \\(\frac{73}{5}\\)
- \\(88\frac{2}{4}\\)
- \\(\frac{203}{10}\\)
in 9–17, estimate each sum or difference.
- \\(\frac{74}{10} + \frac{42}{5}\\)
- \\(14\frac{5}{8} - 3\frac{7}{10}\\)
- \\(\frac{9}{4} + \frac{11}{2} + \frac{43}{4}\\)
- \\(\frac{58}{5} - \frac{49}{12}\\)
- \\(9 + 3\frac{11}{14} + 5\frac{1}{9}\\)
- \\(15\frac{6}{7} - 12\frac{2}{10}\\)
- \\(3\frac{2}{5} + 6\frac{5}{7}\\)
- \\(\frac{61}{3} - \frac{19}{2}\\)
- \\(25\frac{7}{8} + 8\frac{7}{12}\\)
Problem 1: $\boldsymbol{\frac{53}{6}}$ (Round to the nearest whole number)
Step 1: Divide 53 by 6
$53 \div 6 = 8.833\ldots$
Step 2: Round to nearest whole number
Since the decimal part $0.833\ldots \geq 0.5$, we round up. So $8.833\ldots$ rounds to 9.
Step 1: Analyze the fraction part
The fraction is $\frac{8}{9}$, which is very close to 1 (since $\frac{8}{9} \approx 0.888\ldots \geq 0.5$).
Step 2: Round the mixed number
Adding 1 to the whole number part 13, we get $13 + 1 = 14$.
Step 1: Divide 130 by 3
$130 \div 3 = 43.333\ldots$
Step 2: Round to nearest whole number
Since the decimal part $0.333\ldots < 0.5$, we round down to 43.
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