Question

your answer
part 1 of 3
(a) write an equation in terms of x that represents the given relationship.
the equation is $216 = \frac{1}{2}x(x + 6)$.
part 2 of 3
(b) solve the equation to find the dimensions of the given shape. be sure to include the
the base is 18 yd.
part: 2 / 3
part 3 of 3
the height is $\square$.
yd yd² yd³
skip part check

Explanation:

Step1: Analyze the equation structure

The equation given is \(216=\frac{1}{2}x(x + 6)\), and we know the base is \(x = 18\) yd (from part 2). The height is related to \(x\) as \(x+6\) (from the equation structure, since the area of a triangle is \(\frac{1}{2}\times base\times height\), so if base is \(x\), height is \(x + 6\)).

Step2: Calculate the height

Substitute \(x=18\) into the expression for height (\(x + 6\)):
\(18+6=24\)

Answer:

The height is \(\boldsymbol{24}\) yd.