Question

anthony is playing hide - and - seek with vince and jasmine. vince is hiding 20 meters south of anthony, and jasmine is hiding due east of vince. if anthony is 29 meters from jasmine, how far apart are vince and jasmine?
□ meters

Explanation:

Step1: Identify right triangle sides

Anthony, Vince, and Jasmine form a right triangle. Let Anthony's position be $A$, Vince's be $V$, Jasmine's be $J$. $AV = 20$ m, $AJ = 29$ m, right angle at $V$. We need to find $VJ$.

Step2: Apply Pythagorean theorem

Pythagorean theorem: $AJ^2 = AV^2 + VJ^2$. Rearrange to solve for $VJ$:
$VJ = \sqrt{AJ^2 - AV^2}$

Step3: Substitute values and calculate

Substitute $AJ=29$, $AV=20$:
$VJ = \sqrt{29^2 - 20^2} = \sqrt{841 - 400} = \sqrt{441} = 21$

Answer:

21 meters