Question

assignment
subtract the following
with
regrouping using expanded form.
1)
42 = _ + _

• 18 = _ + _

__ + __
2)
94 = _ + _

• 37 = _ + _

__ + __

Explanation:

Step1: Analyze the first subtraction (assuming it's 50 - 42, maybe a typo)

Let's correct the first number to 50 (since 5 - 42 is negative and likely a typo). Expand 50 as \(40 + 10\) and 42 as \(40 + 2\).

Step2: Subtract the expanded forms

\((40 + 10)-(40 + 2)=40 + 10 - 40 - 2=(40 - 40)+(10 - 2)=0 + 8 = 8\)
Wait, maybe the first number is 58 - 42? Let's check the second line: 58 - 18? Let's re - evaluate. Maybe the first problem is 52 - 42? No, the user wrote "5 - 42" which is likely a typo. Let's assume the first problem is 50 - 42:
Expand 50: \(50=40 + 10\)
Expand 42: \(42 = 40+2\)
Subtraction: \((40 + 10)-(40 + 2)=40 - 40+10 - 2 = 8\)
For the second problem, 94 - 37:

Step1: Expand 94 and 37

Expand 94: \(94=80 + 14\) (regrouping: since we can't subtract 7 from 4, we borrow 1 ten from 9 tens, making 9 tens = 8 tens and 4 ones = 14 ones)
Expand 37: \(37 = 30+7\)

Step2: Subtract the expanded forms

\((80 + 14)-(30 + 7)=80 - 30+14 - 7=50 + 7 = 57\)

Wait, maybe the first problem is 58 - 42:
Expand 58: \(58 = 40+18\)
Expand 42: \(42 = 40+2\)
Subtraction: \((40 + 18)-(40 + 2)=40 - 40+18 - 2 = 16\)
And 58 - 18:
Expand 58: \(58 = 40+18\)
Expand 18: \(18 = 10+8\)
Subtraction: \((40 + 18)-(10 + 8)=40 - 10+18 - 8=30 + 10 = 40\)

Since the handwriting is a bit unclear, let's assume the first problem is 50 - 42:

Answer:

For \(50-42\) (assuming correction):
Expanded form: \(50 = 40+10\), \(42 = 40 + 2\)
Subtraction: \((40 + 10)-(40 + 2)=8\)

For \(94 - 37\):
Expanded form: \(94=80 + 14\), \(37 = 30+7\)
Subtraction: \((80 + 14)-(30 + 7)=57\)

(Note: The original problem has some unclear parts, especially the first number "5" which is likely a typo. The above is a best - effort solution based on common subtraction with regrouping problems.)