Question

balance the nuclear reaction. supply 1 symbol and 2 numbers.
151 151 b
sm → eu + a
62 63 c
a = 1
b = 2
c = 3
the type of nuclear reaction is 4 and it emits 5 radiation.
the reaction is not bombardment and so it is 6 and the half - life concept applies.
a. 0 b. 1 c. -1 d. 2 e. 3 f. 4 g. 5 h. 6
i. radiation j. fusion k. none l. fission m. spontaneous
n. electron capture o. bombardment o. α (alpha) q. β (beta)
r. γ (gamma)

Explanation:

Step1: Balance mass - number

The mass - number on the left side is 151 for Sm. On the right side, the mass - number of Eu is 151. For the mass - number to be conserved in the nuclear reaction, the mass - number of particle A (B) must be 0.

Step2: Balance atomic - number

The atomic - number of Sm is 62 and that of Eu is 63. To balance the atomic - number, the atomic - number of particle A (C) must be - 1. A particle with mass - number 0 and atomic - number - 1 is a beta particle ($\beta^-$).

Step3: Identify reaction type

Since a neutron in Sm is converted into a proton, an electron (beta particle) and an antineutrino are emitted. This is a beta - decay reaction. Beta - decay is a spontaneous process as it occurs without external bombardment.

Answer:

A. C. -1
B. A. 0
C. C. -1

1. Q. $\beta$ (beta)
2. Q. $\beta$ (beta)
3. M. spontaneous