Question

1. a bar of soap is 12 cm tall, 6 cm wide, and 10 cm long. it has a mass of 415 grams. what is the density of the bar of soap.

Explanation:

Step1: Calculate volume of soap bar

The volume $V$ of a rectangular - prism (shape of soap bar) is given by $V = l\times w\times h$, where $l = 10$ cm, $w = 6$ cm and $h = 12$ cm. So $V=10\times6\times12 = 720$ $cm^{3}$.

Step2: Calculate density of soap bar

The density $
ho$ is given by the formula $
ho=\frac{m}{V}$, where $m = 415$ g and $V = 720$ $cm^{3}$. So $
ho=\frac{415}{720}\approx0.576$ g/$cm^{3}$.

Answer:

$0.576$ g/$cm^{3}$