Question

a baseball diamond is a square that is 50 feet on each side. a player threw the ball from 2nd base to home. how far did the ball travel? round to the nearest tenth.

Explanation:

Step1: Identify right triangle sides

Each side $a = 60$ ft, $b = 60$ ft

Step2: Apply Pythagorean theorem

$$c = \sqrt{a^2 + b^2}$$

Step3: Substitute values

$$c = \sqrt{60^2 + 60^2} = \sqrt{3600 + 3600}$$

Step4: Calculate and simplify

$$c = \sqrt{7200} = 60\sqrt{2} \approx 84.9$$

Answer:

84.9 ft