Question

below is the final image points b a t after going through a translation rule of : find the pre - image (x + 12, y - 17) where would the pre - image points be located? →b(5, - 29) →a(20, - 19) →t(21, - 4) o b(-7, - 12) a(8, - 2) t(9, 13) o b(7, - 12) a(8, - 2) t(9, - 13) o b(17, - 46) a(32, - 36) t(33, - 21) o b(-7, 12) a(-8, - 2) t(-9, 21)

Explanation:

Step1: Find pre - image x - coordinate

The translation rule for x is \(x'=x + 12\), so to find the pre - image x, we use \(x=x'-12\).
For point \(B'\) with \(x' = 5\), \(x_B=5 - 12=-7\). For point \(A'\) with \(x' = 20\), \(x_A=20 - 12 = 8\). For point \(T'\) with \(x' = 21\), \(x_T=21 - 12=9\).

Step2: Find pre - image y - coordinate

The translation rule for y is \(y'=y - 17\), so to find the pre - image y, we use \(y=y'+17\).
For point \(B'\) with \(y'=-29\), \(y_B=-29 + 17=-12\). For point \(A'\) with \(y'=-19\), \(y_A=-19 + 17=-2\). For point \(T'\) with \(y'=-4\), \(y_T=-4 + 17 = 13\).

Answer:

B (-7,-12) A (8,-2) T (9,13)